The devices in power system shown in Figure 2 have the following ratings G1:100 MVA, 13.8 kV grounde

The devices in power system shown in Figure 2 have the following ratings G1:100 MVA, 13.8 kV grounded Y, X0.15 pu, X2 0.015 pu Xo = 0.05 pu G2:50 MVA, 20.0 kV grounded Y, X0.15 pu, X2-0.015 pu Xo = 0.05 pu T1 100 MVA, 13.8/138 kV (both grounde), X1 0.08 pu, X2- 0.08 pu Xo 0.08 pu T2:50 MVA, 20.0/138 kV, D-Y grounded Y, X10.08 pu, X2- 0.08 pu Xo 0.08 pu L1 : 100 MVA, 138 kV grounded X1= 19 W, X2= 19 w, xo= 50 W Region Region 2 Region 3 Gi Bus 2 YA Figure 2 Assume that all resistances in the power system can be neglected. The system base apparent power is specified by your lecturer)MVA, and the base line voltage is 13.8 kV at bus 1. Assume that the voltage at bus 1 is 13.8 kV and that the power system is initially unloaded (to be Use Matlab to 2a. Find the sub transient per-phase equivalent circuits of this power system for positive-, negative- and zero-sequence component. 2b. Find the subtransient fault current at the fault found at the location indicated by X for: A symmetrical three-phase fault iA single line-to-ground fault iiA line-to-line fault iiA double line-to-ground fault

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